kellerpaula kellerpaula

23-03-2020
Mathematics

contestada

Trigonometry

Trigonometric Equations

0 ≤ x ≤ 2π, solve the equation 2 sin x cos x = sin x

Respuesta :

amna04352 amna04352

23-03-2020

Answer:

x = 0, π/3, π, 5π/3, 2π

Step-by-step explanation:

2sinxcosx = sinx

2sinxcosx - sinx = 0

sinx(2cosx - 1) = 0

sinx = 0, 2cosx-1 = 0

sinx = 0

x = 0, π, 2π

cosx = ½

basic angle = π/3

x = π/3, 2π - π/3 = 5π/3

x = 0, π/3, π, 5π/3, 2π

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