Respuesta :

2Na + I2 —> 2NaI

No. of mol of 4.0g I2 = 4/(35.5x2) = 0.0563

No. of mol of NaI = 2 x 0.0563 = 0.113

No. of molecules of NaI = 0.113 x 6.02 x 10^23 = 6.78 x 10^22

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