cachauwin cachauwin
  • 26-01-2020
  • Mathematics
contestada

Find the value of the polynomial 3xy+7x2−3x2y+3y2x−2x2−2xy+4x2y−2y2x, when x=1 and y=−2

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sqdancefan
sqdancefan sqdancefan
  • 10-02-2021

9514 1404 393

Answer:

  5

Step-by-step explanation:

The evaluation can be easier if terms are collected first.

  3xy+7x^2−3x^2y+3y^2x−2x^2−2xy+4x^2y−2y^2x

  = x^2y(-3+4) +xy^2(3-2) +x^2(7-2) +xy(3-2)

  = x^2y +xy^2 +5x^2 +xy

  = x(xy +y^2 +5x +y)

Filling in the numbers, we have ...

  = (1)(1(-2) +(-2)^2 +5(1) +(-2))

  = -2 +4 +5 -2

  = 5

The value of the polynomial is 5.

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