Answer: 0.33M CaBr2
Explanation: Molarity is expressed in moles of solute over liter solution.
M= n solute / L solution
Solution:
First convert mass of CaBr2 to moles using its molar mass
Ca = 40
Br = 80 x 2 answer is 200 g CaBr2.
50.0g CaBr2 x 1 mole CaBr2 / 200 g CaBr2 = 0.25 moles CaBr2
Next convert mL to L
750.0 mL x 1L / 1000mL
= 0.75 L
Substitute the values for M.
M= 0.25 moles CaBr2/ 0.75 L
= 0.33 M CaBr2
