The sum of first 46 positive and odd numbers is 2116
Solution:
Given that we have to find the sum of first 46 positive and odd numbers
The sum of first "n" natural odd numbers which are positive is given as:
[tex]Sum = n^2[/tex]
Here, n = 46
Therefore,
sum of first 46 positive and odd numbers = [tex]46^2[/tex]
sum of first 46 positive and odd numbers = [tex]46 \times 46 = 2116[/tex]
Thus the sum of first 46 positive and odd numbers is 2116
