Answer: d(5) = 115m
Position after 5 seconds is 115m
Explanation:
Given;
Initial position d(0) = 0
Time = 5 sec
Velocity function vx(t) = 10t - 2
To determine its position after 5 sec we need to calculate the position function.
d(t) = integral of vx(t)
d(t) = ∫10t - 2
d(t) = (10/2)t^2 - 2t + c
d(t) = 5t^2 - 2t + d(0)
c = d(0) = 0
d(t) = 5t^2 - 2t
So, at time t = 5
d(5) = 5(5^2) -2(5) = 125 - 10
d(5) = 115m
