Answer:
D. For domain x =1/4 , [tex] y = 2\frac{1}{16}[/tex]
Step-by-step explanation:
Here, the given function is [tex]f(x) = x^2 + 2[/tex]
or we can also say that [tex]y= x^2 + 2[/tex]
Now, for domain value of x = 1/4
[tex]y(\frac{1}{4} ) = (\frac{1}{4} )^2 + 2 = 2 + \frac{1}{16 } = 2\frac{1}{16}[/tex]
Hence, for domain x =1/4 , [tex] y = 2\frac{1}{16}[/tex]
