spindablock spindablock
  • 21-11-2019
  • Chemistry
contestada

what is the approximate energy of a photon having a frequency of 4 x 10^7 Hz (h=6.6 x 10^-34]•s)

Respuesta :

Neetoo
Neetoo Neetoo
  • 25-11-2019

Answer:

E = 26.4 ×10⁻²⁷ j

Explanation:

Given data:

Energy of energy =?

Frequency = 4×10⁷ Hz

Solution:

Formula:

E = hf

E = hf

E =  6.6  ×10⁻³⁴ m²Kg/s  . 4×10⁷ Hz

Hz = s⁻¹

j = m²Kg/s ²

E = 26.4 ×10⁻²⁷ j.

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