For this case we must solve the following product:
[tex](2x-y) (3x + y) =[/tex]
We apply distributive property considering that:
[tex]+ * + = +\\+ * - = -[/tex]
So:
[tex](2x) (3x) + (2x) (y) - (y) (3x) - (y) (y) =[/tex]
To multiply powers of the same base, the same base is placed and the exponents are added:
[tex]6x^{1 + 1} + 2xy-3xy-y^{1 + 1} =[/tex]
Different signs are subtracted and the sign of the major is placed:
[tex]6x ^ 2-xy-y ^ 2[/tex]
So, the solution is: [tex]6x ^ 2-xy-y ^ 2[/tex]
Answer:
Option A
