scovarrubio39
scovarrubio39 scovarrubio39
  • 22-10-2019
  • Mathematics
contestada

Which of the following systems of equations has no solution?
A. x - 2y = 2
x - 2y = 4
B. x + 2y = 7
x=y
C. x-y=0
x+y=1
D. x-y=1
x=2y​

Respuesta :

frika
frika frika
  • 26-10-2019

Answer:

A

Step-by-step explanation:

The system of two equations

[tex]\left\{\begin{array}{l}a_1x+b_1y=c_1\\ \\a_2x+b_2y=c_2\end{array}\right.[/tex]

has no solutions, when

[tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq \dfrac{c_1}{c_2}[/tex]

In option A,

[tex]a_1=1,\ b_1=-2,\ c_1=2\\ \\a_2=1,\ b_2=-2,\ c_2=4[/tex]

and

[tex]\dfrac{1}{1}=\dfrac{-2}{-2}\neq \dfrac{2}{4}[/tex]

so this system has no solutions.

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