Answer:x=14.35
Step-by-step explanation:
Given
[tex] \sqrt{2x}+15=x+6[/tex]
[tex]\sqrt{2x}=x-9[/tex]
Squaring Both sides
[tex]2x=\left ( x-9\right )^2[/tex]
[tex]2x=x^2+81-18x[/tex]
[tex]x^2-20x+81=0[/tex]
[tex]x=\frac{20\pm \sqrt{20^2-4\times 81}}{2}[/tex]
[tex]x=\frac{20\pm 8.717}{2}[/tex]
[tex]x=5.64, 14.35[/tex]
For x=5.64 value of [tex]\sqrt{2x}= negative[/tex]
therefore x=5.64 is not a root of equation
