aleclaube79 aleclaube79
  • 21-10-2019
  • Mathematics
contestada

The length of a rectangle is 3cm more than twice it’s width. Find the largest possible length if the perimeter is at most 66cm

Respuesta :

Аноним Аноним
  • 21-10-2019

l = 3 + 2w

2l + 2w = perimeter

66 = 2(3 + 2w) + 2w

2 * 3 = 6

2 * 2w = 4w

6 + 4w + 2w = 66

4w + 2w = 6w

6 + 6w = 66

-6

6w = 60

/6

w = 10

Width = 10

l = 3 + 2 * 10

2 * 10 = 20

20 + 3 = 23

23 = l

23 * 2 + 10 * 2

46 + 20 = 66

The largest possible length is 23cm.

The largest possible total length is 46cm.

Answer Link

Otras preguntas

Mr. Walton ordered 12 pizzas for the art class celebrattion. one fourth of the pizzas had only mushrooms. how many of the pizzas had only mushrroms?
At 8:00 am, a building casts a shadow 75 feet long. The angle where the ray from the sun met the ground is 50°. How tall is the building?
what was the main goal of European explorers in the 1500s?
What's the answer to log1/3 27 = ?
If x² - y² = 55, and x - y = 11, then y =
What times what equals 576?
If x² - y² = 55, and x - y = 11, then y =
logb121=2   Can somebody help and explain?
What is the diameter of a sphere with a volume of 288 pi? Also can you show me the work
Ok so I have like a grid and it says "On the grid to the right, draw a polygon that has 2 pairs of parallel sides, 2 pairs of sides equal in length, and 2 acute