Answer:(x,y)=(2.5,1)
Step-by-step explanation:
Given
[tex]2^{2x+y-1}=32[/tex]
[tex]2^{2x+y-1}=2^5[/tex]
thus on comparing
2x+y=6------1
[tex]4^{x-2y}=2[/tex]
[tex]2^{2(x-2y)}=2[/tex]
On comparing exponent of 2
[tex]x-2y=\frac{1}{2}[/tex] ------2
we get x=2.5
substitute x in 1
y=1
(x,y)=(2.5,1)
