Answer:
[tex]x=4[/tex]
Step-by-step explanation:
subtract [tex]\sqrt{3x-12}[/tex] from both sides:
[tex]\sqrt{2x-8}=-\sqrt{3x-12}[/tex]
square to both sides:
[tex](\sqrt{2x-8})^{2} =-(\sqrt{3x-12})^{2} \\2x-8=-(3x-12)[/tex]
Add 3x-12 to both sides:
[tex]2x-8+3x-12=0\\5x-20=0[/tex]
Add 20to both sides:
[tex]5x=20[/tex]
Finally, Divide both sides by 5:
[tex]x=\frac{20}{5}=4[/tex]
