ramsey9603 ramsey9603
  • 21-10-2019
  • Mathematics
contestada

Prove that if x > 1, then a triangle with side lengths x^2 − 1, 2x, and x^2+ 1 is a right triangle.

Respuesta :

arindamvutla arindamvutla
  • 02-11-2019

Answer:

See the explanation.

Step-by-step explanation:

If a triangle is a right triangle, then it should follow pythagoras theorem.

So sum of squares of two sides is equal to the square of the third longest side.

[tex](x^{2} -1 )^{2}   = x^{4} - 2 x^{2}  + 1[/tex]

[tex](x^{2} +1 )^{2}   = x^{4} + 2 x^{2}  + 1[/tex]

[tex](2x)^{2}  = 4x^{2}[/tex]

Adding the first and third equation we get the second equation.

So it follows Pythagoras theorem.

Hence it is a right triangle with [tex]x^{2} + 1[/tex] as the hypotenuse.

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