s7harrycraycar
s7harrycraycar s7harrycraycar
  • 25-05-2016
  • Mathematics
contestada

What are the roots of the polynomial equation x^3-7x=6x-12?

a. –6, 6
b. –4, 1, 3
c. –3, –1, 4
d. 1, 3

Respuesta :

caylus
caylus caylus
  • 25-05-2016
Hello,

Answer B

P(x)=x^3-13x+12
P(1)=1-13+12=0 ==>1 is root
P(3)=3^3-13*3+12=0 ==>3 is root
P(-4)=(-4)^3-13*(-4)+12=0 is root

P(x)=(x-1)(x-3)(x+4)

Answer Link
camjai21 camjai21
  • 03-11-2020

Answer:

b

Step-by-step explanation:

Answer Link

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