Answer:
[tex]1.05\times 10^{-26}J[/tex]
Explanation:
The uncertainty in energy is given by [tex]\Delta E=\frac{h}{2\pi \Delta t}[/tex]
here h is plank's constant which value is [tex]6.67\times 10^{-34}[/tex] and [tex]\Delta t[/tex] is the time interval which is given as [tex]1.2\times 10^{-8}sec[/tex]
So using all the parameters the smallest possible uncertainty in electrons energy is [tex]=\frac{6.67\times 10^{-34}}{2\times \pi \times 1.2\times 10^{-8}}=1.05\times 10^{-26}J[/tex]
