sreynoso7331 sreynoso7331
  • 23-07-2019
  • Mathematics
contestada

express x^2-5x+8 in the form (x-a)^2+b where a and b are top-heavy fractions.

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Luv2Teach
Luv2Teach Luv2Teach
  • 02-08-2019

Answer:

Step-by-step explanation:

That a and b are actually h and k, the coordinates of the vertex of the parabola.  There is a formula to find h:

[tex]h=\frac{-b}{2a}[/tex]

then when you find h, sub it back into the original equation to find k.  For us, a = 1, b = -5, and c = 8:

[tex]h=\frac{-(-5)}{2(1)}=\frac{5}{2}[/tex]

so h (or a) = 5/2

Now we sub that value in for x to find k (or b):

[tex]k=1(\frac{5}{2})^2-5(\frac{5}{2})+8[/tex]

and k (or b) = 7/4.

Rewriting in vertex form:

[tex](x-\frac{5}{2})^2+\frac{7}{4}[/tex]

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