Answer:
16
Step-by-step explanation:
we know that
[tex]a^{\frac{n}{m}}=\sqrt[m]{a^{n}}[/tex]
In this problem we have
[tex](-64)^{\frac{2}{3}}[/tex]
therefore
[tex]a=-64[/tex]
[tex]n=2[/tex]
[tex]m=3[/tex]
substitute
[tex](-64)^{\frac{2}{3}}=\sqrt[3]{(-64)^{2}}[/tex]
Remember that
[tex]64=4^{3}[/tex]
substitute
[tex]\sqrt[3]{(-4^{3})^{2}}=\sqrt[3]{(-4^{2})^{3}}=\sqrt[3]{(16)^{3}}=16[/tex]
