Respuesta :

Answer:

b

Step-by-step explanation:

Given

[tex]\frac{x^2-2x-3}{4x^2-12}[/tex]

Substitute x = 3 into the expression

= [tex]\frac{3^2-2(3)-3}{4(3)^2-12}[/tex]

= [tex]\frac{9-6-3}{36-12}[/tex]

= [tex]\frac{0}{24}[/tex] = 0 → b

Answer:

b

Step-by-step explanation:

the answer is b:0

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