sharpeyennifer sharpeyennifer
  • 21-05-2019
  • Mathematics
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condense 2log4 + log3 - log2 + log5

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Danutz98
Danutz98 Danutz98
  • 21-05-2019

[tex]2\log4 + \log3 -\log2 + \log5= \\ \\ = \log 2^4+ \log3 -\log2 + \log5 = \\ \\ = \log 16+ \log3 -\log2 + \log5 = \\ \\ = \log\Big(16\cdot 3:2\cdot 5\Big) = \log\Big(\dfrac{16\cdot 3\cdot 5}{2}\Big) = \log(8\cdot 3\cdot 5) = \\ \\ =\log120[/tex]

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