Answer:
[tex](x+3)^2 + (y-4)^2 = 1[/tex]
Step-by-step explanation:
Equation of a circle can be found by
[tex](x-a)^2 + (y-b)^2 = r^2[/tex]
Given center 3,-4 i.e
a= 3 and b=-4
and radius r = 1
Putting the values of a,b and r in the equation we get:
[tex](x-(-3))^2 + (y-4)^2 =(1)^2\\(x+3)^2 + (y-4)^2 = 1[/tex]
