aveannleach
aveannleach aveannleach
  • 25-04-2019
  • Mathematics
contestada

Can someone please help with NUMBER 7?!! It’s my last one I will mark brainliest to the best answer

Can someone please help with NUMBER 7 Its my last one I will mark brainliest to the best answer class=

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 25-04-2019

Answer:

1, 3, 9, 27

Step-by-step explanation:

[tex] a_n = 3^{n - 1} [/tex]

You need the first 4 terms, so let n = 1, and evaluate the expression. Then do the same for n = 2, n = 3, and finally n = 4.

n = 1

[tex] a_1 = 3^{1 - 1} = 3^0 = 1 [/tex]

n = 2

[tex] a_2 = 3^{2 - 1} = 3^1 = 3 [/tex]

n = 3

[tex] a_3 = 3^{3 - 1} = 3^2 = 9 [/tex]

n = 4

[tex] a_4 = 3^{4 - 1} = 3^3 = 27 [/tex]

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