Here is your answer
[tex] \frac{9}{16} \pi \: {units}^{2} [/tex]
REASON:
Circumference(C)= 2πr
, where r is radius
Given
C= (3/2) π
So,
[tex]2\pi \: r = \frac{3}{2}\pi[/tex]
[tex]r = \frac{\frac{3}{2}\pi}{2\pi}[/tex]
[tex]r = \frac{3}{4} [/tex]
Now,
[tex]area = \pi {r}^{2} [/tex]
[tex] = \pi \times { (\frac{3}{4}) }^{2} [/tex]
[tex] = \frac{9}{16}\pi \: {unit}^{2} [/tex]
HOPE IT IS USEFUL
