Answer: It's because a triple of threes was moved outside of the radical.
Step-by-step explanation:
[tex]\sqrt[3]{4\times5\times2\times5\times7} = \\\sqrt[3]{2\times2\times5\times2\times5\times7} = \\\sqrt[3]{2\times2\times2\times5\times5\times7} = \\\sqrt[3]{2\times2\times2}\sqrt[3]{5\times5\times7} = \\2\sqrt[3]{5\times5\times7}[/tex]
