[tex]lim_{x \rightarrow 0} \dfrac{xcsc(2x)}{cos(5x)} = \dfrac{0}{0} \\\therefore\\lim_{x \rightarrow 0} \dfrac{xcsc(2x)}{cos(5x)} = lim_{x \rightarrow 0} \dfrac{x}{sin(2x)cos(5x)}\\= lim_{x \rightarrow 0} \dfrac{1}{2cos(2x)cos(5x) -5sin(2x)sin(5x)} = \dfrac{1}{2}[/tex]
