kimmmmmmm41 kimmmmmmm41
  • 22-10-2018
  • Mathematics
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For what value of n does (1/36)^n=216

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 22-10-2018

(1/36)^n = 216

Rewrite 36 as 6^2

(1/6^2) ^n = 216

Since 36 is in the denominator, the exponent is negative

(6^-2) ^n = 216

Rewrite 216 as 6^3

(6^-2)^n = 6^3

We know that a^b^c = a^(b*c) so

6^(-2n) = 6^3

Since the bases are the same, the exponents are the same

-2n = 3

Solving for n

n =-3/2

n = -1.5

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