Consider the cube of the number 4,
[tex]4^3 = 4 \times 4 \times 4 = 64[/tex]
Now, we have to take the cube root of the result obtained which is 64.
So, [tex](64)^\frac{1}{3} = (4 \times 4 \times 4)^\frac{1}{3}[/tex]
[tex](64)^\frac{1}{3} = (4^3)^\frac{1}{3}[/tex]
[tex](64)^\frac{1}{3} = (4)^{3 \times \frac{1}{3}}[/tex]
[tex](64)^\frac{1}{3} = 4[/tex]
Therefore, the cube root of 64 is 4.
But Diego evaluated the result as 8, which is incorrect.
Therefore, Diego is incorrect.
